tag:blogger.com,1999:blog-2809673787839142835.post4624963458236098129..comments2023-06-19T01:35:56.639-07:00Comments on Freelancing web and computer tools: CIE 9709 Pure Maths Paper 3, May/June 2013 - question 9Unknownnoreply@blogger.comBlogger4125tag:blogger.com,1999:blog-2809673787839142835.post-58443861314914914782013-05-23T12:08:00.112-07:002013-05-23T12:08:00.112-07:00the longest distance from origin to any point in t...the longest distance from origin to any point in the shaded region is representing the modulus of z<br /><br />in my case I can calculate the exact value of z to check the inequlities<br />z=a+bi<br />2a^2=4 ==> a=root(2)<br />b=2+root(2)<br />z= root(2)+ (2+root(2))i<br />z-2i=root2 + root(2)i ==> |z-2i|=2<br />z+2 = 2+root(2) +(2+root(2))i<br />arg(z+2)=pi/4scalarhttps://www.blogger.com/profile/04677227278962240426noreply@blogger.comtag:blogger.com,1999:blog-2809673787839142835.post-90595577185617462752013-05-23T11:54:09.790-07:002013-05-23T11:54:09.790-07:00how to check?
for example by taking your value of...how to check?<br /><br />for example by taking your value of z?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2809673787839142835.post-37929250315196086532013-05-23T11:52:41.500-07:002013-05-23T11:52:41.500-07:00what you calculated is the length of the line conn...what you calculated is the length of the line connecting A with the point (-2,0). <br />did you get the same shaded region? did you check if your z is satisfying both inequalities?<br />z can be any point in the shaded region - magnitude of it is the length of the line connecting the point representing z to the originscalarhttps://www.blogger.com/profile/04677227278962240426noreply@blogger.comtag:blogger.com,1999:blog-2809673787839142835.post-44107434078617862272013-05-23T10:40:25.089-07:002013-05-23T10:40:25.089-07:00I think the greatest possible modulus of z was {(2...I think the greatest possible modulus of z was {(2^2 + 2^2)^0.5 + r(=2)}=4.83?Anonymousnoreply@blogger.com